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← IIT-JEE 2011 · Paper 1
MathematicsSingle correct+3 / -1Question 59 of 69

IIT-JEE 2011 · Paper 1, Mathematics question 59

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Paragraph for Question Nos. 58 to 60

Let aa, bb and cc be three real numbers satisfying
[abc][197827737]=[000](E)\begin{bmatrix}a&b&c\end{bmatrix}\begin{bmatrix}1&9&7\\8&2&7\\7&3&7\end{bmatrix}=\begin{bmatrix}0&0&0\end{bmatrix}\qquad\text{(E)}

Let ω\omega be a solution of x3−1=0x^3-1=0 with Im⁡(ω)>0\operatorname{Im}(\omega)>0. If a=2a=2 with bb and cc satisfying (E), then the value of
3ωa+1ωb+3ωc\frac3{\omega^a}+\frac1{\omega^b}+\frac3{\omega^c}
is equal to

Choose one option
Answer and worked solution

Official answer: A

Values. a=2a=2 gives k=−2k=-2: b=12b=12, c=−14c=-14.

Sum. 3ω2+1ω12+3ω−14=3ω+1+3ω14=3ω+1+3ω2=1+3(−1)=−2\dfrac3{\omega^2}+\dfrac1{\omega^{12}}+\dfrac3{\omega^{-14}}=3\omega+1+3\omega^{14}=3\omega+1+3\omega^2=1+3(-1)=-2.

(A)