IIT-JEE 2011 · Paper 1 · Chemistry Q14

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ChemistrySingle correct+3 / -1Question 14 of 69

Passage

Paragraph for Question Nos. 12 to 14

When a metal rod M is dipped into an aqueous colourless concentrated solution of compound N, the solution turns light blue. Addition of aqueous NaCl to the blue solution gives a white precipitate O. Addition of aqueous $\ce{NH3}$ dissolves O and gives an intense blue solution.

The final solution contains

\ce{[Pb(NH3)4]^{2+}}

and

\ce{[CoCl4]^{2-}}

\ce{[Al(NH3)4]^{3+}}

and

\ce{[Cu(NH3)4]^{2+}}

\ce{[Ag(NH3)2]+}

and

\ce{[Cu(NH3)4]^{2+}}

\ce{[Ag(NH3)2]+}

and

\ce{[Ni(NH3)6]^{2+}}

Answer and worked solution

Official answer: C

With ammonia: $\ce{AgCl + 2NH3 -> [Ag(NH3)2]+ + Cl-}$ and $\ce{Cu^{2+} + 4NH3 -> [Cu(NH3)4]^{2+}}$ (intense blue).

(C)

Topics:Stability and applications Cation analysis

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IIT-JEE 2011 · Paper 1, Chemistry question 14