IIT-JEE 2011 · Paper 1 · Chemistry Q4 · Dronacharya Exams

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ChemistrySingle correct+3 / -1Question 4 of 69

Dissolving 120 g of urea (mol. wt. 60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution is

A

1.78 M

B

2.00 M

C

2.05 M

D

2.22 M

Answer and worked solution

Official answer: C

Volume. Mass of solution $120+1000=1120$ g, volume $\dfrac{1120}{1.15}=973.9$ mL.

Molarity. $\dfrac{120/60}{0.9739}=2.05$ M.

(C)

Topics:Concentration terms

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