IIT-JEE 2010 · Paper 2 · Physics Q45

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PhysicsInteger+3Question 45 of 57

A diatomic ideal gas is compressed adiabatically to $\dfrac1{32}$ of its initial volume. In the initial temperature of the gas is $T_i$ (in Kelvin) and the final temperature is $aT_i$ , the value of $a$ is

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Answer and worked solution

Official answer: 4

Adiabatic. $TV^{\gamma-1}=$ const with $\gamma=\frac75$ :
$\frac{T_f}{T_i}=\left(\frac{V_i}{V_f}\right)^{2/5}=32^{2/5}=4.$

Answer: 4

Topics:Thermodynamic processes

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IIT-JEE 2010 · Paper 2, Physics question 45