IIT-JEE 2010 · Paper 2 · Chemistry Q8

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ChemistryInteger+3Question 8 of 57

Total number of geometrical isomers for the complex $\ce{[RhCl(CO)(PPh3)(NH3)]}$ is

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Answer and worked solution

Official answer: 3

Square-planar $\ce{[MABCD]}$ . Rh(I) is $d^8$ , square planar. With four different ligands, fix A (Cl); the ligand trans to it can be any of the other three (CO, $\ce{PPh3}$ or $\ce{NH3}$ ), and each choice fixes the arrangement. So there are 3 geometrical isomers.

Answer: 3

Topics:Isomerism in complexes

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IIT-JEE 2010 · Paper 2, Chemistry question 8