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← IIT-JEE 2010 · Paper 1
MathematicsSingle correct+3 / -1Question 42 of 84

IIT-JEE 2010 · Paper 1, Mathematics question 42

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Paragraph for Questions 42 to 44

Let p be an odd prime number and TpT_p be the following set of 2×22\times2 matrices:
Tp={A=[abca]:a,b,c∈{0,1,2,…,p−1}}T_p=\left\{A=\begin{bmatrix}a&b\\c&a\end{bmatrix}:a,b,c\in\{0,1,2,\ldots,p-1\}\right\}

The number of A in TpT_p such that A is either symmetric or skew-symmetric or both, and det (A) divisible by p is

Choose one option
Answer and worked solution

Official answer: D

Symmetric means b=cb=c; then det⁡A=a2−b2=(a−b)(a+b)\det A=a^2-b^2=(a-b)(a+b), divisible by the prime pp when a≡ba\equiv b or a≡−b(modp)a\equiv-b\pmod p.

  • a=ba=b: pp matrices.
  • a+b=pa+b=p with 1≤a≤p−11\le a\le p-1: p−1p-1 matrices (these have a≠ba\ne b since pp is odd).

Skew-symmetric needs a=0a=0 and c=−bc=-b; with entries in {0,…,p−1}\{0,\ldots,p-1\} only the zero matrix qualifies, already counted.

Total. p+(p−1)=2p−1p+(p-1)=2p-1.

(D)