IIT-JEE 2010 · Paper 1 · Chemistry Q28

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ChemistryInteger+3Question 28 of 84

The number of neutrons emitted when $^{235}_{92}\mathrm U$ undergoes controlled nuclear fission to $^{142}_{54}\mathrm{Xe}$ and $^{90}_{38}\mathrm{Sr}$ is

Your answer

Answer and worked solution

Official answer: 4

Fission (induced by one neutron):
$\ce{^{235}_{92}U + ^1_0n -> ^{142}_{54}Xe + ^{90}_{38}Sr + x\,^1_0n}.$

Balance. Charge: $92=54+38$ . Mass: $236=142+90+x$ , so $x=4$ .

Answer: 4

Topics:Radioactive decay kinetics

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IIT-JEE 2010 · Paper 1, Chemistry question 28