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← IIT-JEE 2010 · Paper 1
ChemistryInteger+3Question 26 of 84

IIT-JEE 2010 · Paper 1, Chemistry question 26

A student performs a titration with different burettes and finds titre values of 25.2 mL, 25.25 mL, and 25.0 mL. The number of significant figures in the average titre value is

Answer and worked solution

Official answer: 3

Average. 25.2+25.25+25.03=25.15\dfrac{25.2+25.25+25.0}3=25.15 mL.

Precision. The result cannot be more precise than the least precise reading, which has one decimal place (25.2, 25.0). So the average is reported as 25.2 mL: 3 significant figures.

Answer: 3