IIT-JEE 2010 · Paper 1 · Chemistry Q1

← IIT-JEE 2010 · Paper 1

ChemistrySingle correct+3 / -1Question 1 of 84

The correct structure of ethylenediaminetetraacetic acid (EDTA) is

(HOOC-CH₂)₂N-CH=CH-N(CH₂-COOH)₂: two N atoms joined by a CH=CH bridge, each carrying two CH₂COOH groups.

(HOOC)₂N-CH₂-CH₂-N(COOH)₂: two N atoms joined by CH₂CH₂, each carrying two COOH groups directly on N.

(HOOC-CH₂)₂N-CH₂-CH₂-N(CH₂-COOH)₂: ethylenediamine with four CH₂COOH groups on the two N atoms.

HOOC-CH₂-NH-CH(CH₂COOH)-CH(CH₂COOH)-NH-CH₂-COOH: two NH groups on adjacent CH carbons, each CH carrying a CH₂COOH.

Answer and worked solution

Official answer: C

EDTA is ethylenediamine ( $\ce{H2N-CH2CH2-NH2}$ ) with all four N-H hydrogens replaced by carboxymethyl groups:
$\ce{(HOOCCH2)2N-CH2CH2-N(CH2COOH)2}.$
(A) has a CH=CH bridge, (B) has COOH directly on N, and (D) is a different skeleton.

(C)

Topics:Stability and applications IUPAC nomenclature

Next question →

IIT-JEE 2010 · Paper 1, Chemistry question 1