IIT-JEE 2009 · Paper 2 · Physics Q39

PhysicsSingle correct+3 / -1Question 39 of 57

The mass $M$ shown in the figure oscillates in simple harmonic motion with amplitude $A$ . The amplitude of the point P is

\dfrac{k_1A}{k_2}

\dfrac{k_2A}{k_1}

\dfrac{k_1A}{k_1+k_2}

\dfrac{k_2A}{k_1+k_2}

Answer and worked solution

Official answer: D

Springs in series. The massless junction P transmits the same force: $k_1x_1=k_2x_2$ , with $x_1+x_2=A$ at the extreme.

Displacement of P (the stretch of $k_1$ ):
$x_1=\frac{k_2A}{k_1+k_2}.$

(D)

Topics:Spring-mass systems

IIT-JEE 2009 · Paper 2, Physics question 39