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← IIT-JEE 2009 · Paper 2
ChemistryInteger+4 / -1Question 16 of 57

IIT-JEE 2009 · Paper 2, Chemistry question 16

The oxidation number of Mn in the product of alkaline oxidative fusion of MnOX2\ce{MnO2} is

Answer and worked solution

Official answer: 6

Alkaline oxidative fusion. 2 MnOX2+4 KOH+OX2→2 KX2MnOX4+2 HX2O\ce{2MnO2 + 4KOH + O2 -> 2K2MnO4 + 2H2O}. In manganate MnOX4X2−\ce{MnO4^{2-}}, Mn is +6.

Answer: 6

Topics:Important compounds (KMnO4, K2Cr2O7)Oxidation number
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