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← IIT-JEE 2009 · Paper 2
ChemistryMultiple correct+4 / -1Question 5 of 57

IIT-JEE 2009 · Paper 2, Chemistry question 5

For the reduction of NOX3X−\ce{NO3-} ion in an aqueous solution, E∘E^\circ is +0.96 V. Values of E∘E^\circ for some metal ions are given below

Half-reaction E∘E^\circ
VX2+(aq)+2 eX−→V\ce{V^{2+}(aq) + 2e- -> V} −1.19 V
FeX3+(aq)+3 eX−→Fe\ce{Fe^{3+}(aq) + 3e- -> Fe} −0.04 V
AuX3+(aq)+3 eX−→Au\ce{Au^{3+}(aq) + 3e- -> Au} +1.40 V
HgX2+(aq)+2 eX−→Hg\ce{Hg^{2+}(aq) + 2e- -> Hg} +0.86 V

The pair(s) of metals that is(are) oxidized by NOX3X−\ce{NO3-} in aqueous solution is(are)

Choose one or more options
Answer and worked solution

Official answer: A, B, D

Rule. NOX3X−\ce{NO3-} (E∘=+0.96E^\circ=+0.96 V) can oxidise a metal whose reduction potential is lower than 0.96 V.

  • V (−1.19), Fe (−0.04) and Hg (+0.86) are oxidised.
  • Au (+1.40) is not.

So every pair without Au works: V and Hg, Hg and Fe, Fe and V.

(A), (B), (D)

Topics:Galvanic cells and EMFOxidation number
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