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← IIT-JEE 2009 · Paper 1
PhysicsSingle correct+3 / -1Question 43 of 60

IIT-JEE 2009 · Paper 1, Physics question 43

A ball is dropped from a height of 20 m above the surface of water in a lake. The refractive index of water is 4/3. A fish inside the lake, in the line of fall of the ball, is looking at the ball. At an instant, when the ball is 12.8 m above the water surface, the fish sees the speed of ball as [Take g=10 m/s2g=10\ \mathrm{m/s^2}.]

Choose one option
Answer and worked solution

Official answer: C

Ball's speed. It has fallen 20−12.8=7.220-12.8=7.2 m: v=2(10)(7.2)=12v=\sqrt{2(10)(7.2)}=12 m/s.

Apparent position. Seen from inside water, a height hh above the surface appears at μh\mu h (near-normal viewing), so the apparent speed is μv=43×12=16\mu v=\frac43\times12=16 m/s.

(C)