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← IIT-JEE 2009 · Paper 1
MathematicsMatrix match+8Question 40 of 60

IIT-JEE 2009 · Paper 1, Mathematics question 40

Match the conics in Column I with the statements/expressions in Column II.

Column I

  • A
    Circle
  • B
    Parabola
  • C
    Ellipse
  • D
    Hyperbola

Column II

  • P
    The locus of the point (h,k)(h,k) for which the line hx+ky=1hx+ky=1 touches the circle x2+y2=4x^2+y^2=4
  • Q
    Points zz in the complex plane satisfying ∣z+2∣−∣z−2∣=±3|z+2|-|z-2|=\pm3
  • R
    Points of the conic have parametric representation x=3(1−t21+t2)x=\sqrt3\left(\dfrac{1-t^2}{1+t^2}\right), y=2t1+t2y=\dfrac{2t}{1+t^2}
  • S
    The eccentricity of the conic lies in the interval 1≤x<∞1\le x<\infty
  • T
    Points zz in the complex plane satisfying Re⁡(z+1)2=∣z∣2+1\operatorname{Re}(z+1)^2=|z|^2+1
Mark every match for each entry
PQRST
A
B
C
D
Answer and worked solution

Official answer: A → P; B → S, T; C → R; D → Q, S

  • P: hx+ky=1hx+ky=1 touches x2+y2=4x^2+y^2=4 when 1h2+k2=2\dfrac1{\sqrt{h^2+k^2}}=2: h2+k2=14h^2+k^2=\frac14, a circle.
  • Q: ∣∣z+2∣−∣z−2∣∣=3<4\big||z+2|-|z-2|\big|=3<4: a hyperbola with foci ±2\pm2.
  • R: x=3cos⁡ϕx=\sqrt3\cos\phi, y=sin⁡ϕy=\sin\phi with t=tan⁡ϕ2t=\tan\frac\phi2: the ellipse x23+y2=1\frac{x^2}3+y^2=1.
  • S: eccentricity at least 1: parabola (e=1e=1) or hyperbola (e>1e>1).
  • T: (x+1)2−y2=x2+y2+1(x+1)^2-y^2=x^2+y^2+1 gives y2=xy^2=x, a parabola.

Answer: A → P; B → S, T; C → R; D → Q, S