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← IIT-JEE 2009 · Paper 1
MathematicsSingle correct+3 / -1Question 28 of 60

IIT-JEE 2009 · Paper 1, Mathematics question 28

The number of seven digit integers, with sum of the digits equal to 10 and formed by using the digits 1, 2 and 3 only, is

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Answer and worked solution

Official answer: C

Excess over all ones. Seven digits each at least 1 sum to 7, so the extra 3 must be shared out, with no digit getting more than 2 extra.

  • One digit 3 (extra 2) and one digit 2 (extra 1): 7×6=427\times6=42.
  • Three digits equal to 2: (73)=35\binom73=35.

Total 42+35=7742+35=77.

(C)