A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S.
The structures of the products Q and R, respectively, are
Answer and worked solution
Official answer: A
Q. Cyclisation of the cation Ph−CH=C(Me)−CX+MeX2 onto the ortho carbon gives 1,1,2-trimethyl-1H-indene (C1 bears two Me, the C2=C3 double bond carries a Me at C2).
R. Ozonolysis cleaves C2=C3: C3 (attached to the ring) becomes CHO and C2 becomes a methyl ketone, still attached to CMeX2: R=2-(1,1-dimethyl-2-oxopropyl)benzaldehyde,OHC−CX6HX4−CMeX2−COCHX3.