IIT-JEE 2009 · Paper 1 · Chemistry Q5

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ChemistrySingle correct+3 / -1Question 5 of 60

The reaction of $\ce{P4}$ with X leads selectively to $\ce{P4O6}$ . The X is

Dry

\ce{O2}

A mixture of

\ce{O2}

and

\ce{N2}

Moist

\ce{O2}

\ce{O2}

in the presence of aqueous NaOH

Answer and worked solution

Official answer: B

Limited oxygen. $\ce{P4}$ burns to $\ce{P4O10}$ in excess oxygen. In a limited supply of oxygen it gives $\ce{P4O6}$ ; a mixture of $\ce{O2}$ and $\ce{N2}$ (diluted oxygen) is used so that oxidation stops at $\ce{P4O6}$ . Moisture or NaOH would give acids or phosphine/hypophosphite instead.

(B)

Topics:Group 15

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IIT-JEE 2009 · Paper 1, Chemistry question 5