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← IIT-JEE 2008 · Paper 2
MathematicsSingle correct+3 / -1Question 6 of 66

IIT-JEE 2008 · Paper 2, Mathematics question 6

An experiment has 10 equally likely outcomes. Let AA and BB be two non-empty events of the experiment. If AA consists of 4 outcomes, the number of outcomes that BB must have so that AA and BB are independent, is

Choose one option
Answer and worked solution

Official answer: D

Independence. P(A∩B)=P(A)P(B)P(A\cap B)=P(A)P(B) with P(A)=410P(A)=\frac4{10} and P(B)=b10P(B)=\frac b{10}:
∣A∩B∣10=4b100  ⟹  ∣A∩B∣=2b5.\frac{|A\cap B|}{10}=\frac{4b}{100}\implies|A\cap B|=\frac{2b}5.
This must be a whole number, so bb is a multiple of 5: b=5b=5 (with ∣A∩B∣=2|A\cap B|=2) or b=10b=10.

(D)