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← IIT-JEE 2008 · Paper 2
ChemistryMatrix match+6Question 64 of 66

IIT-JEE 2008 · Paper 2, Chemistry question 64

Match the compounds in Column I with their characteristic test(s)/reaction(s) given in Column II. Indicate your answer by darkening the appropriate bubbles of the 4 × 4 matrix given in the ORS.

Column I

  • A
    HX2N−NHX3X+ClX−\ce{H2N-NH3+Cl-}
  • B
    HO−CX6HX4−CH(NHX3X+I−)COOH\ce{HO-C6H4-CH(NH3+I-)COOH} (4-hydroxyphenylglycine hydroiodide)
  • C
    HO−CX6HX4−NHX3X+ClX−\ce{HO-C6H4-NH3+Cl-} (4-hydroxyanilinium chloride)
  • D
    (OX2N)X2CX6HX3−NH−NHX3X+BrX−\ce{(O2N)2C6H3-NH-NH3+Br-} (2,4-dinitrophenylhydrazinium bromide)

Column II

  • P
    sodium fusion extract of the compound gives Prussian blue colour with FeSOX4\ce{FeSO4}
  • Q
    gives positive FeClX3\ce{FeCl3} test
  • R
    gives white precipitate with AgNOX3\ce{AgNO3}
  • S
    reacts with aldehydes to form the corresponding hydrazone derivative
Mark every match for each entry
PQRS
A
B
C
D
Answer and worked solution

Official answer: A → R; B → P, Q; C → P, Q, R; D → P

  • A, hydrazine hydrochloride. No carbon, so the sodium-fusion extract has no cyanide (no Prussian blue). The chloride gives white AgCl. → R. (It also forms hydrazones with aldehydes, S, which the key accepts as an alternative.)
  • B. Contains C and N (Prussian blue, P) and a phenolic OH (violet with FeClX3\ce{FeCl3}, Q). The iodide gives a yellow AgI precipitate, not white. → P, Q.
  • C, 4-hydroxyanilinium chloride. C and N (P), phenol (Q), chloride (white AgCl, R). → P, Q, R.
  • D, 2,4-dinitrophenylhydrazinium bromide. C and N (P); AgBr is pale yellow, not white. → P. (As a hydrazine it also forms hydrazones, S, accepted as an alternative.)

Answer: A → R; B → P, Q; C → P, Q, R; D → P (the key also accepts A → R, S and D → P, S)