IIT-JEE 2008 · Paper 2 · Chemistry Q53

← IIT-JEE 2008 · Paper 2

ChemistrySingle correct+3 / -1Question 53 of 66

Solubility product constants ( $K_{sp}$ ) of salts of types MX, MX₂ and M₃X at temperature 'T' are $4.0\times10^{-8}$ , $3.2\times10^{-14}$ and $2.7\times10^{-15}$ , respectively. Solubilities (mol dm⁻³) of the salts at temperature 'T' are in the order

MX > MX₂ > M₃X

M₃X > MX₂ > MX

MX₂ > M₃X > MX

MX > M₃X > MX₂

Answer and worked solution

Official answer: D

Solubilities.

MX: $s^2=4.0\times10^{-8}$ , $s=2\times10^{-4}$ .
$\ce{MX2}$ : $4s^3=3.2\times10^{-14}$ , $s^3=8\times10^{-15}$ , $s=2\times10^{-5}$ .
$\ce{M3X}$ : $27s^4=2.7\times10^{-15}$ , $s^4=10^{-16}$ , $s=10^{-4}$ .

Order. $\ce{MX}>\ce{M3X}>\ce{MX2}$ .

(D)

Topics:Solubility product

← Previous question Next question →

IIT-JEE 2008 · Paper 2, Chemistry question 53