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← IIT-JEE 2008 · Paper 1
PhysicsMultiple correct+4 / -1Question 32 of 69

IIT-JEE 2008 · Paper 1, Physics question 32

A particle of mass mm and charge qq, moving with velocity VV enters Region II normal to the boundary as shown in the figure. Region II has a uniform magnetic field BB perpendicular to the plane of the paper. The length of the Region II is ℓ\ell. Choose the correct choice(s).

Three regions side by side: Region I (left), Region II (a strip of width ℓ filled with crosses, i.e. a magnetic field into the page) and Region III (right). A particle moving right with velocity V enters Region II perpendicular to its left boundary.
Choose one or more options
Answer and worked solution

Official answer: A, C, D

Radius of the circular path in Region II: r=mVqBr=\dfrac{mV}{qB}.

  • (A) The particle crosses the strip only if r>ℓr>\ell, i.e. V>qℓBmV>\dfrac{q\ell B}m. True; (B) false.
  • (C) If r≤ℓr\le\ell it turns back along a semicircle, path length πr\pi r, growing with VV. If r>ℓr>\ell it leaves after an arc of angle θ=sin⁡−1ℓr<π2\theta=\sin^{-1}\frac\ell r<\frac\pi2, length rθr\theta, which is less than πℓ\pi\ell (it falls from π2ℓ\frac\pi2\ell towards ℓ\ell as rr grows). The longest path, πℓ\pi\ell, is at r=ℓr=\ell, i.e. V=qℓBmV=\dfrac{q\ell B}m. True.
  • (D) A particle that returns to Region I always traces a semicircle, taking half a period πmqB\dfrac{\pi m}{qB}, independent of VV. True.

(A), (C), (D)