IIT-JEE 2008 · Paper 1 · Physics Q28

PhysicsSingle correct+3 / -1Question 28 of 69

An ideal gas is expanding such that $PT^2=$ constant. The coefficient of volume expansion of the gas is

\dfrac1T

\dfrac2T

\dfrac3T

\dfrac4T

Answer and worked solution

Official answer: C

Relation between V and T. $PV=nRT$ with $P=\dfrac k{T^2}$ gives $V=\dfrac{nR}kT^3$ .

Coefficient of volume expansion.
$\gamma=\frac1V\frac{dV}{dT}=\frac3T.$

(C)

Topics:Temperature and thermal expansion Ideal gas equation

IIT-JEE 2008 · Paper 1, Physics question 28