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← IIT-JEE 2008 · Paper 1
MathematicsSingle correct+3 / -1Question 1 of 69

IIT-JEE 2008 · Paper 1, Mathematics question 1

Consider the two curves
C1:y2=4x,C2:x2+y2−6x+1=0.C_1:y^2=4x,\qquad C_2:x^2+y^2-6x+1=0.
Then,

Choose one option
Answer and worked solution

Official answer: B

Intersect. Put y2=4xy^2=4x into the circle:
x2+4x−6x+1=0  ⟹  (x−1)2=0.x^2+4x-6x+1=0\implies(x-1)^2=0.
The only common abscissa is the double root x=1x=1, giving y=±2y=\pm2.

Touching. A double root means the curves meet tangentially, at the two points (1,2)(1,2) and (1,−2)(1,-2).

(B)