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ChemistryMatrix match+6Question 42 of 66

IIT-JEE 2007 · Paper 2, Chemistry question 42

Match the reactions in Column I with nature of the reactions/type of the products in Column II. Indicate your answer by darkening the appropriate bubbles of the 4 × 4 matrix given in the ORS.

Column I

  • A
    OX2X−→OX2+OX2X2−\ce{O2- -> O2 + O2^{2-}}
  • B
    CrOX4X2−+HX+→\ce{CrO4^{2-} + H+ ->}
  • C
    MnOX4X−+NOX2X−+HX+→\ce{MnO4- + NO2- + H+ ->}
  • D
    NOX3X−+HX2SOX4+FeX2+→\ce{NO3- + H2SO4 + Fe^{2+} ->}

Column II

  • P
    redox reaction
  • Q
    one of the products has trigonal planar structure
  • R
    dimeric bridged tetrahedral metal ion
  • S
    disproportionation
Mark every match for each entry
PQRS
A
B
C
D
Answer and worked solution

Official answer: A → P, S; B → R; C → P, Q; D → P

  • A, 2 OX2X−→OX2+OX2X2−\ce{2O2- -> O2 + O2^{2-}}: oxygen goes from −½ to 0 and −1, so it is a redox disproportionation. → P, S.
  • B, 2 CrOX4X2−+2 HX+→CrX2OX7X2−+HX2O\ce{2CrO4^{2-} + 2H+ -> Cr2O7^{2-} + H2O}: not redox (Cr stays +6); dichromate is two CrOX4\ce{CrO4} tetrahedra sharing an oxygen. → R.
  • C, 2 MnOX4X−+5 NOX2X−+6 HX+→2 MnX2++5 NOX3X−+3 HX2O\ce{2MnO4- + 5NO2- + 6H+ -> 2Mn^{2+} + 5NO3- + 3H2O}: redox, and NOX3X−\ce{NO3-} is trigonal planar. → P, Q.
  • D, brown-ring test: NOX3X−+3 FeX2++4 HX+→NO+3 FeX3++2 HX2O\ce{NO3- + 3Fe^{2+} + 4H+ -> NO + 3Fe^{3+} + 2H2O}, then [Fe(HX2O)X5NO]X2+\ce{[Fe(H2O)5NO]^{2+}} forms; a redox reaction. → P.

Answer: A → P, S; B → R; C → P, Q; D → P

Topics:Oxidation numberImportant compounds (KMnO4, K2Cr2O7)Anion analysis
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