Skip to content
dronacharya.ai
← IIT-JEE 2007 · Paper 1
MathematicsSingle correct+4 / -1Question 63 of 66

IIT-JEE 2007 · Paper 1, Mathematics question 63

Passage

Paragraph for Question Nos. 61 to 63

Consider the circle x2+y2=9x^2+y^2=9 and the parabola y2=8xy^2=8x. They intersect at PP and QQ in the first and the fourth quadrants, respectively. Tangents to the circle at PP and QQ intersect the xx-axis at RR and tangents to the parabola at PP and QQ intersect the xx-axis at SS.

The radius of the incircle of the triangle PQRPQR is

Choose one option
Answer and worked solution

Official answer: D

Sides of PQR. PQ=42PQ=4\sqrt2, PR=QR=62PR=QR=6\sqrt2, so s=82s=8\sqrt2.

Area. 12⋅42⋅8=162\frac12\cdot4\sqrt2\cdot8=16\sqrt2.

Inradius. r=Δs=16282=2r=\dfrac\Delta s=\dfrac{16\sqrt2}{8\sqrt2}=2.

(D)