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← IIT-JEE 2007 · Paper 1
MathematicsSingle correct+4 / -1Question 59 of 66

IIT-JEE 2007 · Paper 1, Mathematics question 59

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Paragraph for Question Nos. 58 to 60

Let VrV_r denote the sum of the first rr terms of an arithmetic progression (A.P.) whose first term is rr and the common difference is (2r−1)(2r-1). Let
Tr=Vr+1−Vr−2andQr=Tr+1−Trfor r=1,2,…T_r=V_{r+1}-V_r-2\quad\text{and}\quad Q_r=T_{r+1}-T_r\quad\text{for }r=1,2,\ldots

TrT_r is always

Choose one option
Answer and worked solution

Official answer: D

Difference. From Vr=2r3−r2+r2V_r=\frac{2r^3-r^2+r}2,
Vr+1−Vr=2(3r2+3r+1)−(2r+1)+12=3r2+2r+1.V_{r+1}-V_r=\frac{2(3r^2+3r+1)-(2r+1)+1}2=3r^2+2r+1.

So Tr=3r2+2r−1=(3r−1)(r+1)T_r=3r^2+2r-1=(3r-1)(r+1). Both factors are at least 2 for r≥1r\ge1, so TrT_r is always composite (T1=4T_1=4, T2=15T_2=15, …). It is not always odd or always even.

(D)