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ChemistryMatrix match+6Question 44 of 66

IIT-JEE 2007 · Paper 1, Chemistry question 44

Match gases under specified conditions listed in Column I with their properties/laws in Column II. Indicate your answer by darkening the appropriate bubbles of the 4 × 4 matrix given in the ORS.

Column I

  • A
    hydrogen gas (P=200P=200 atm, T=273T=273 K)
  • B
    hydrogen gas (P∼0P\sim0, T=273T=273 K)
  • C
    COX2\ce{CO2} (P=1P=1 atm, T=273T=273 K)
  • D
    real gas with very large molar volume

Column II

  • P
    compressibility factor ≠1\ne1
  • Q
    attractive forces are dominant
  • R
    PV=nRTPV=nRT
  • S
    P(V−nb)=nRTP(V-nb)=nRT
Mark every match for each entry
PQRS
A
B
C
D
Answer and worked solution

Official answer: A → P, S; B → R; C → P, Q; D → P, S

  • A, H₂ at 200 atm: repulsion (finite molecular volume) dominates, Z>1Z>1; the behaviour follows P(V−nb)=nRTP(V-nb)=nRT. → P, S.
  • B, H₂ as P→0P\to0: ideal behaviour, PV=nRTPV=nRT. → R.
  • C, CO₂ at 1 atm, 273 K: an easily liquefied gas; attractive forces dominate and Z<1Z<1. → P, Q.
  • D, real gas with very large molar volume: the official key gives P, S. (Physically, at very large molar volume both corrections become negligible and the gas approaches PV=nRTPV=nRT, i.e. R; the key is reproduced as printed.)

Answer: A → P, S; B → R; C → P, Q; D → P, S

Topics:Real gases and van der Waals equation
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