IIT-JEE 2007 · Paper 1 · Chemistry Q24

ChemistrySingle correct+3 / -1Question 24 of 66

Among the following, the paramagnetic compound is

\ce{Na2O2}

\ce{O3}

\ce{N2O}

\ce{KO2}

Answer and worked solution

Official answer: D

$\ce{Na2O2}$ : peroxide $\ce{O2^{2-}}$ , all electrons paired.
$\ce{O3}$ and $\ce{N2O}$ : even-electron molecules with paired electrons, diamagnetic.
$\ce{KO2}$ : superoxide $\ce{O2-}$ has one unpaired electron in a π* orbital, paramagnetic.

(D)

Topics:Molecular orbital theory Group 16

IIT-JEE 2007 · Paper 1, Chemistry question 24